Operator Overloading (Example)

Example code:
#include<iostream>
using namespace std;
class student{
    int a;
    int b;
    string name;
public:
    student(){
        a=0;
        b=0;
        name="No name.";
    }
    student(int a,int b,string name){
        this->a=a;
        this->b=b;
        this->name=name;
    }
    void print(){
        cout<<"a = "<<a<<endl;
        cout<<"b = "<<b<<endl;
        cout<<"Name = "<<name<<endl;
    }
    student operator +(student ob);
};
student student::operator +(student ob){
    ob.a=a+ob.a;
    ob.b=b+ob.b;
    name=name+" ";
    ob.name=name+ob.name;
    return ob;
}
int main(){
    student ob1(1,40,"Hasibul"),ob2(2,33,"Hassan"),ob3;
    ob1.print();
    ob2.print();
    ob3=ob1+ob2;
    ob3.print();
    return 0;
}
Output:

Limitation of overloading:

I. We never create new operator.
ii.  Some of them we can not use.
`    1) "." Dote operator.
     2) ".*" Direct Pointer.
     3) "()?:" Terinary operator. 
     4) "::" Scope Resolution.
     5) "sizeof".
     6) "#" Preprocessor..